**1)** How long does it take from the Elvis TT (Elvis cracking the door at the end) for Elvis to reach the console on the bridge? In other words, **what is the shortest amount of time the first Skedar can uncloak, after Elvis cracking the door?**

I estimated this to be "around 11 seconds" and in order for my math to work, I need this as "exact as possible."

The TAS cracks the Elvis door at 2:40.18 and fires a shot at the first Skedar at 2:51.31, a time of 11.13 seconds.

https://youtu.be/18jZHOwdYME?t=39m27s

Assuming the TAS has the Skedar uncloak at the first moment possible, then 11.13 (11 seconds and 4 frames?) is the number I'm looking for.

Elvis reaching console is completely irrelevant, he shouldn't even have to be at the console for the uncloaking to start. As the facts topic post says, the only TT that actually matters is when you kill the last skedar on the bridge. Elvis opening the door is also irrelevant and

inconsistent up to at least half a second, but since this is the TT that's been used historically, we'll continue using it here. This means:

1. From last bridge skedar kill -> First possible uncloak = 23.33 seconds.

2. From elvis opening door -> First possible uncloak = 23.33 - 12.39 (+- 0.21) = 10.94 (+- 0.21)

This fits well with your TAS timing.

**2) How long does it take for the 2nd Skedar, once uncloaked, to open the next door?**

This is hugely important as this knowledge makes it possible for me to estimate when the 2nd Skedar uncloaked (sent out his clone.

in the TAS, the 2nd door does not get cracked until 2:54.80, a full 2.49 seconds after the first Skedar uncloaks. Does this sound correct? Does it really take about 2.5 seconds for this Skedar to reach the door and open it? In this case, I would have to assume that the TAS also has the 2nd Skedar's clone uncloak at the very first moment possible (2:51.31) and it takes about 2.5 sec for this to take place.

By knowing how long this takes, I can reverse engineer when the 2nd Skedar uncloaked to figure out how likely this was.

For thought: Chuya's 2nd Skedar cracks open the door 2.23 seconds after the first one spawns. This can be accounted for because the first one doesn't quite spawn at the "earliest" possible moment, but it means the 2nd Skedar spawned before the first one. In Chuya's case specifically, the first Skedar spawns after about 2s, which would mean the second Skedar spawned after about 1.7s.

My facts topic post states: "It then takes around 3.3 seconds before he opens the door (though slower is possible)."

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A bit more in-depth analysis of the TAS:

Last bridge skedar kill: ~2:27:68

Elvis opening door: ~2:40:05 (after 12.37 seconds, roughly 0.19 slower than fastest)

First skedar kill: ~2:51:31 (after 23.63 seconds, .3 slower than fastest possible)

Second door opening: ~2:54:80 (after 27.21 seconds, 3.88 seconds after earliest possible spawn, and if it takes at least 3.3 seconds to reach door after spawn, he must've spawned within 0.58 seconds)

Third skedar kill: ~2:55:36 (0.56 seconds after second, 4.35 seconds after spawning starts. In order words, the TAS is sub-optimal and loses roughly a second compared to a "perfect" ending, half a second on the 2nd skedar spawn, and another half a second on the 3rd)

This makes sense since Miikka didn't have the knowledge that we now do when making the TAS, and simply went for the fastest ending he could get (I wasn't involved since I stopped working on the TAS after Crash Site, and Miikka did the rest of the stages). The odds of an optimal ending (ignoring 1st skedar) is (if i'm not totally mistaken) (1/256)^2 = 0.001526%. We want 2nd skedar to spawn ASAP, which is 1/256. And since the 3rd skedar can't spawn until 2nd is shot, the outcomes of his first ~66 cycles ((~3.3 seconds * 60 frames per second) / ~3 frames per cycle) don't matter. Only the ~67th cycle matters which is again, 1/256.